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NEET 2026 Physics Question 7 Solution

Topic: Nuclear Physics · Official NTA Booklet Code 50
NEET 2026 Physics Question 7: Alpha Decay Q-Value Energy Calculation in keV

Question

Consider the following nuclear reaction: ²³⁸U → ²³⁴Th + ⁴He. Take masses of ²³⁸U, ²³⁴Th and ⁴He as 238.050 u, 234.043 u and 4.003 u, respectively. The Q value for the reaction, in keV, is: [Given: 1 u = 931.5 MeV c⁻²]

✓
Verified Against NTA Final Answer Key
Option (1) : Q = 3726 keV
📚 Nuclear Physics Easy
📋 Given Parameters & Problem Setup
Nuclear Reaction ^{238}U -> ^{234}Th + ^4He
Mass of ^{238}U 238.050 u
Mass of ^{234}Th 234.043 u
Mass of ^4He 4.003 u
Mass-Energy Equivalence 1 u = 931.5 MeV/c^2
Target Unit Q value in keV (kiloelectron-volts)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Mass Defect in Milliatomic Units

⏱️ Eliminates unit conversion confusion between MeV and keV.

Compute mass defect in thousandths of u and convert directly to keV

1 Total product mass = 234.043 + 4.003 = 238.046 u.
2 Mass defect Delta m = 238.050 - 238.046 = 0.004 u (4 milli-u).
3 1 u = 931.5 MeV = 931,500 keV.
4 Q = 0.004 * 931,500 keV = 4 * 931.5 = 3726 keV. Done in 20 seconds!
🛡️
Why You Can 100% Trust This Shortcut: Conservation of mass-energy: Q = [m(parent) - sum(m(daughters))] * c^2. Since 1 u = 931.5 MeV, multiplying by 10^3 gives keV directly: 0.004 * 931.5 * 1000 = 3726 keV.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Calculate Total Mass of Decay Products

Sum the masses of the thorium daughter nucleus and the alpha particle:

mproducts=m(234Th)+m(4He)=234.043 u+4.003 u=238.046 um_{\text{products}} = m(^{234}\text{Th}) + m(^4\text{He}) = 234.043\text{ u} + 4.003\text{ u} = 238.046\text{ u}
  • • Carry all decimal places carefully: 234.043 + 4.003 = 238.046 u.
Step 2

Calculate the Mass Defect (Delta m)

Subtract product mass from the parent uranium mass:

Δm=m(238U)−mproducts=238.050 u−238.046 u=0.004 u\Delta m = m(^{238}\text{U}) - m_{\text{products}} = 238.050\text{ u} - 238.046\text{ u} = 0.004\text{ u}
  • • Positive mass defect confirms the alpha decay is energetically spontaneous (exothermic).
Step 3

Convert Mass Defect to Energy in keV

Multiply mass defect by energy equivalent per atomic mass unit:

Q=Δm×931.5 MeV=0.004×931.5=3.726 MeVQ = \Delta m \times 931.5\text{ MeV} = 0.004 \times 931.5 = 3.726\text{ MeV}
  • • Convert MeV to keV: 1 MeV = 1000 keV.
  • • Q = 3.726 * 1000 keV = 3726 keV.
  • • Matches Option (1) exactly.
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 Option (1)
✓ 100% Correct
Verdict & Scientific Reason:

Exact mathematical calculation matching Official NTA Final Answer Key.

💡
Why this is airtight: Careful subtraction and accurate conversion from MeV to keV.
Note: Zero rounding error.
2 Option (2)
✗ Incorrect
Verdict & Scientific Reason:

Rounding error.

⚠️
Student Fallacy (Why candidates pick this trap): Rounds 931.5 to 932 or makes an arithmetic addition error.
Note: NTA provides 931.5 to test exact calculation without coarse rounding.
3 Option (3)
✗ Incorrect
Verdict & Scientific Reason:

Calculation drift.

⚠️
Student Fallacy (Why candidates pick this trap): Uses Delta m = 0.00401 u or arithmetic carry-over error.
Note: 238.050 - 238.046 is exactly 0.004.
4 Option (4)
✗ Incorrect
Verdict & Scientific Reason:

Arbitrary distractor.

⚠️
Student Fallacy (Why candidates pick this trap): Rounds 931.5 to 935.
Note: Always use the exact value given in the question header: 931.5 MeV.
⚠️

NTA Trap Alert: The Unit Conversion Oversight (MeV vs keV)

Students who calculate 3.726 often get confused looking for 3.726 in the options, forgetting that the question specifically requests energy in keV.

🛡️ How to avoid the -1 mark: Always circle the requested physical unit in the question stem before starting calculation.
📖

Core NEET Syllabus Standard

NEET UG Physics Core Standards · Nuclei Standard Benchmark
Core Scientific Principle Tested:

"Q = [M_parent - (M_daughter + M_alpha)] * c^2 = Delta m * 931.5 MeV."

Syllabus Focus: Q-Value of Nuclear Reactions and Alpha Decay Energetics
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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