NEET 2023 Physics Question 2 Solution
Question
The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to (1/16)th of its initial value?
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The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to (1/16)th of its initial value?
1/16 is (1/2)⁴, which means exactly 4 half-lives; 4 × 20 min = 80 min done in 5 seconds!
The activity A of a radioactive sample at time t is related to its initial activity A₀ through the number of elapsed half-lives n:
Given that the activity drops to 1/16th of its initial value:
Multiply the number of half-lives by the duration of one half-life:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Exactly 4 half-lives of 20 minutes each equals 80 minutes.
Represents only 1 half-life, where activity drops to 1/2, not 1/16.
Represents 2 half-lives, where activity drops to (1/2)² = 1/4.
Represents 3 half-lives, where activity drops to (1/2)³ = 1/8.
Aspirants often confuse powers of 2 (2, 4, 8, 16 -> n=4) with squares (4²=16 -> incorrectly picking n=2, leading to 40 minutes).
"Every half-life reduces the remaining active nuclei and activity by an exact factor of 2."
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