NEET 2023 Physics Question 3 Solution
Question
The temperature of a gas is −50°C. To what temperature the gas should be heated so that the rms speed is increased by 3 times?
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The temperature of a gas is −50°C. To what temperature the gas should be heated so that the rms speed is increased by 3 times?
"Increased BY 3 times" means v₂ = v₁ + 3v₁ = 4v₁! Thus T₂ = 4² × T₁ = 16 × 223 K = 3568 K → 3295° C!
Gas law relations must strictly be calculated in Kelvin (absolute temperature):
Root mean square velocity of an ideal gas molecule of molar mass M is given by:
The velocity increases BY 3 times its initial value, which makes the new velocity 4 times the original:
Square the velocity ratio to find the final absolute temperature, then convert back to Celsius:
Convert back to degrees Celsius:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
This is merely the initial temperature in Kelvin, representing zero change.
Completely erroneous linear temperature extrapolation.
Matches exact thermodynamic derivation accounting for v₂ = 4v₁ and conversion to Celsius.
Numerical distractor resulting from miscalculated intermediate subtraction.
Over 45% of students read "increased by 3 times" as "increased TO 3 times", taking v₂ = 3v₁ instead of v₂ = 4v₁. Furthermore, calculating in Celsius without converting to Kelvin first creates complete havoc.
"RMS velocity of gas molecules is directly proportional to the square root of absolute temperature in Kelvin."
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