NEET 2023 Physics Question 1 Solution
Question
The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is:
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The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is:
Energy formula is U = (1/2) L I²; plug 4 μH and 2 A directly to get 0.5 × 4 × 4 = 8 μJ in 10 seconds!
An inductor stores energy in its magnetic field when a current flows through it. The work done in establishing current I against the self-induced back emf is obtained by integrating dW = L i di from 0 to I:
Substitute the given numerical parameters into the expression with appropriate SI conversion:
Convert Joules into microjoules (μJ) using 1 μJ = 10⁻⁶ J:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Accurate value derived from U = (1/2) L I² with exact microjoule unit matching.
Underestimates energy by a factor of 2.
Incorrect magnitude and wrong metric prefix.
Value has correct numerical coefficient (8) but incorrect prefix (milli instead of micro).
NTA intentionally pairs 8 μJ alongside 8 mJ to penalize students who calculate the number 8 correctly on paper but bubble the wrong metric unit.
"The energy stored in an inductor is purely magnetic and proportional to the square of the instantaneous current (U = 1/2 L I²)."
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