Q.52 Chemistry ⭐ 360° Option Elimination Active

NEET 2025 Chemistry Question 52 Solution

Topic: The p-Block Elements (Group 15) · Official NTA Booklet Code 45

Question

Given below are two statements: Statement I: Like nitrogen that can form ammonia, arsenic can form arsine. Statement II: Antimony cannot form antimony pentoxide. In the light of the above statements, choose the most appropriate answer from the options given below:

(1)Both Statement I and Statement II are correct
(2)Both Statement I and Statement II are incorrect
(3)Statement I is correct but Statement II is incorrect
(4)Statement I is incorrect but Statement II is correct

✓

Verified Against NTA Final Answer Key

Option (3) : Statement I is correct but Statement II is incorrect

📚 The p-Block Elements (Group 15) Easy

📋 Given Parameters & Problem Setup

Statement I Like nitrogen that can form ammonia, arsenic can form arsine.

Statement II Antimony cannot form antimony pentoxide.

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The 30-Second Exam Hall Shortcut: ⚡ Group 15 Hydride & Pentoxide Fact Check

⏱️ Save ~30 seconds

Group 15 hydrides: NH₃, PH₃, AsH₃ (arsine), SbH₃, BiH₃ all exist ⟹ Statement I is TRUE! Group 15 oxides: Sb forms Sb₂O₃ and Sb₂O₅ (antimony pentoxide) ⟹ Statement II is FALSE!

1 Check Statement I: Arsenic forms the canonical hydride AsH₃, known as arsine (analogous to ammonia NH₃ and phosphine PH₃). Statement I is CORRECT.

2 Check Statement II: Antimony readily forms both trioxide (Sb₂O₃) and pentoxide (Sb₂O₅). The statement claims antimony CANNOT form antimony pentoxide, which is completely false! (Only bismuth fails to form a stable +5 oxide due to inert pair effect).

3 Conclusion: Statement I is correct but Statement II is incorrect.

4 Match Option (3) in under 15 seconds!

🛡️

Why You Can 100% Trust This Shortcut: Group 15 Hydride & Oxide Trends (NCERT Chemistry · p-Block Elements).

📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Evaluate Statement I (Hydride Formation in Group 15)

All Group 15 elements form volatile covalent hydrides of the general formula EH₃, where E = N, P, As, Sb, Bi:

\text{Nitrogen forms Ammonia (NH}_3), \quad \text{Arsenic forms Arsine (AsH}_3)

• Arsine (AsH₃) is a well-known, highly toxic gas formed by the reduction of arsenic compounds.
• Therefore, Statement I is unequivocally CORRECT.

Step 2

Evaluate Statement II (Oxide Formation in Group 15)

Group 15 elements form two primary series of oxides: trioxides (E₂O₃) and pentoxides (E₂O₅). The oxidation state of the element in the pentoxide is +5:

\text{Antimony forms Antimony Trioxide (Sb}_2\text{O}_3) \text{ and Antimony Pentoxide (Sb}_2\text{O}_5)

• Antimony pentoxide (Sb₂O₅) is synthesized by oxidizing antimony or antimony trioxide with concentrated nitric acid.
• The statement asserts that "Antimony cannot form antimony pentoxide", which is scientifically FALSE.
• (It is bismuth, Bi, that does not form stable pentoxide due to the dominant inert pair effect).

Step 3

Select Matching Option

Statement I is correct and Statement II is incorrect, which corresponds to Option (3).

\text{Statement I: True}, \quad \text{Statement II: False} \implies \text{Option (3)}

• 100% aligned with the official NTA Final Answer Key.

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan

1 A

✗ Incorrect

Verdict & Scientific Reason:

Incorrect. Statement II is false because antimony pentoxide Sb₂O₅ exists.

⚠️

Student Fallacy (Why candidates pick this trap): Believing antimony cannot achieve the +5 oxidation state.

2 B

✗ Incorrect

Verdict & Scientific Reason:

Incorrect. Statement I is true (arsine AsH₃ exists).

⚠️

Student Fallacy (Why candidates pick this trap): Failing to recognize arsine as the hydride of arsenic.

3 C

✓ 100% Correct

Verdict & Scientific Reason:

100% correct. As forms AsH₃ (arsine), and Sb forms Sb₂O₅ (antimony pentoxide).

💡

Why this is airtight: None; rigorous p-block descriptive chemistry.

4 D

✗ Incorrect

Verdict & Scientific Reason:

Incorrect. Inverts the truth values of both statements.

⚠️

Student Fallacy (Why candidates pick this trap): Total reversal of group 15 facts.

⚠️

NTA Trap Alert: Confusing Antimony (Sb) with Bismuth (Bi) Inert Pair Effect

Candidates know that the +5 oxidation state becomes unstable down Group 15 due to the inert pair effect. But this instability causes the absence of pentoxides specifically in BISMUTH (Bi₂O₅ does not exist as a stable oxide), whereas Antimony (Sb) readily forms Sb₂O₅!

🛡️ How to avoid the -1 mark: Remember: Inert pair effect prevents +5 oxide in Bismuth, NOT in Antimony!

📖

Core NEET Syllabus Standard

NEET Chemistry Core Syllabus · The p-Block Elements Standard Benchmark

Core Scientific Principle Tested:

"Group 15 elements form hydrides EH₃ (including AsH₃) and oxides E₂O₃/E₂O₅ (Sb forms Sb₂O₅)."

Syllabus Focus: Group 15 Elements: Hydrides and Oxides

✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

As forms Arsine (True); Sb forms Sb₂O₅ (so "cannot form" is False) ⟹ Statement I correct, II incorrect!

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NEET 2025 Chemistry Question 52 Solution

Question

The 30-Second Exam Hall Shortcut: ⚡ Group 15 Hydride & Pentoxide Fact Check

Step-by-Step Rigorous Workflow & Mathematical Proof

Evaluate Statement I (Hydride Formation in Group 15)

Evaluate Statement II (Oxide Formation in Group 15)

Select Matching Option

360° Option Elimination Engine Key Feature

NTA Trap Alert: Confusing Antimony (Sb) with Bismuth (Bi) Inert Pair Effect

Core NEET Syllabus Standard

Ready to attempt under real exam pressure?

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