MyCompetitiveExams Logo MyCompetitiveExams
MyCompetitiveExams Logo MyCompetitiveExams
Search 1,140+ Questions
Chapters, formulas, speed tricks
→
⚡ Brahmastra NEET 2027
720 MARKS

Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.

Launch Brahmastra 2027 Test →
Start Practice →
100% Free · No Login Required
Q.52 Chemistry · Section A ⭐ 360° Option Elimination Active
Vault ↗

NEET 2024 Chemistry Question 52 Solution

Topic: Hydrocarbons · Official NTA Booklet Code T1
NEET 2024 Chemistry Question 52: Boiling Points of Isomeric Alkanes and Effect of Branching

Question

Given below are two statements: Statement I: The boiling point of three isomeric pentanes follows the order n-pentane > isopentane > neopentane Statement II: When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point. In the light of the above statements, choose the most appropriate answer from the options given below:

✓
Verified Against NTA Final Answer Key
Option (3) : Both Statement I and Statement II are correct.
📚 Hydrocarbons Easy
📋 Given Parameters & Problem Setup
Isomers n-pentane, isopentane (2-methylbutane), neopentane (2,2-dimethylpropane)
Statement I Boiling point order: n-pentane > isopentane > neopentane
Statement II Branching gives spherical shape, smaller surface area, weaker intermolecular forces, lowering boiling point
⚡

The 30-Second Exam Hall Shortcut: ⚡ Branching vs Boiling Point Rule

⏱️ Save ~35 seconds

More Branches -> More Spherical -> Minimum Surface Area -> Weakest van der Waals forces -> Lowest Boiling Point!

1 n-pentane has a continuous straight chain with maximal surface area of contact (b.p. = 309.1 K).
2 isopentane has one methyl branch (b.p. = 301 K).
3 neopentane is highly branched and symmetrical, adopting a nearly spherical shape with minimal surface area (b.p. = 282.5 K).
4 Boiling point sequence: n-pentane > isopentane > neopentane -> Statement I is TRUE.
5 Statement II provides the exact theoretical rationale -> Statement II is TRUE.
6 Both statements are correct -> Option (3)!
🛡️
Why You Can 100% Trust This Shortcut: NCERT Chemistry · Hydrocarbons (Intermolecular forces and physical properties of isomeric alkanes).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Analysis of Statement I (Boiling Point Data)

For constitutional isomers of formula C5H12, the experimental boiling points decrease monotonically with increasing branching: n-pentane (309.1 K) > isopentane / 2-methylbutane (301.0 K) > neopentane / 2,2-dimethylpropane (282.5 K). Hence, Statement I is correct.

Tb(n-pentane)>Tb(isopentane)>Tb(neopentane)T_b(\text{n-pentane}) > T_b(\text{isopentane}) > T_b(\text{neopentane})
Step 2

Analysis of Statement II (Structural and Intermolecular Mechanism)

Van der Waals dispersion forces act across the contact surface between neighboring molecules. As branching increases, molecular geometry becomes compact and approaches a sphere. Because a sphere possesses the minimum surface area for a given volume, intermolecular contact area diminishes, weakening London dispersion forces and lowering the boiling point. Hence, Statement II is correct.

Branching↑  ⟹  Surface Area↓  ⟹  van der Waals forces↓  ⟹  Tb↓\text{Branching} \uparrow \implies \text{Surface Area} \downarrow \implies \text{van der Waals forces} \downarrow \implies T_b \downarrow
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

Statement II is the precise NCERT scientific explanation.

⚠️
Student Fallacy (Why candidates pick this trap): Believing spherical shape increases intermolecular contact.
2 (2)
✗ Incorrect
Verdict & Scientific Reason:

Statement I is an established empirical truth.

⚠️
Student Fallacy (Why candidates pick this trap): Thinking branching raises boiling point.
3 (3)
✓ 100% Correct
Verdict & Scientific Reason:

Both empirical trend and mechanistic explanation are 100% sound.

💡
Why this is airtight: None.
4 (4)
✗ Incorrect
Verdict & Scientific Reason:

Both statements are completely valid.

⚠️
Student Fallacy (Why candidates pick this trap): Total rejection of organic structure-property relationship.
⚠️

NTA Trap Alert: Confusing Boiling Point with Melting Point in Neopentane

Neopentane has a high melting point (256.5 K) due to crystal packing symmetry, but its boiling point is the lowest (282.5 K) due to low surface area.

🛡️ How to avoid the -1 mark: Distinguish liquid vaporization (surface contact area governs boiling point) from crystal lattice packing (symmetry governs melting point).
📖

Core NEET Syllabus Standard

Chemistry Core Organic Chemistry · Hydrocarbons Standard Benchmark
Core Scientific Principle Tested:

"Among isomeric alkanes, straight-chain isomers have higher boiling points than branched-chain isomers due to greater van der Waals contact area."

Syllabus Focus: Alkanes: Physical Properties and Intermolecular Forces
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
Branches make a ball, balls touch the least, boiling drops fast when branches increase!

Ready to attempt under real exam pressure?

Test your speed and accuracy in the authentic 200-minute timed NTA simulator.

Launch NEET 2024 CBT Test →

Spotted a mistake in this solution? Report an error (support@mycompetitiveexams.com)

⚖️ Legal & Fair Dealing Notice: Sourced from publicly released NEET 2024 question papers and NEET answer keys for private study, research, and non-commercial educational practice under Fair Dealing (Section 52(1)(a) of the Indian Copyright Act, 1957). Not affiliated with or endorsed by NTA or NMC.

Solve 4 NEET Questions a Day — One per Subject

Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.