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NEET 2023 Chemistry Question 90 Solution

Topic: Hydrocarbons · Official NTA Booklet Code G5

Question

Consider the following compounds/species: i. naphthalene ii. cyclopentadienyl anion iii. cyclobutadiene iv. cyclopropenyl anion v. cyclopropenyl cation vi. cyclooctatetraene vii. anthracene. The number of compounds/species which obey Huckel's rule is ___.

✓

Verified Against NTA Final Answer Key

Option (2) : 4

📚 Hydrocarbons Medium

📋 Given Parameters & Problem Setup

Species evaluated i. Naphthalene, ii. Cyclopentadienyl anion, iii. Cyclobutadiene, iv. Cyclopropenyl anion, v. Cyclopropenyl cation, vi. Cyclooctatetraene, vii. Anthracene

Rule to test Hückel’s Rule ((4n + 2) π electrons, cyclic, planar, fully conjugated)

⚡

The 30-Second Exam Hall Shortcut: ⚡ Hückel’s Magic Numbers: 2, 6, 10, 14 π Electrons in Planar Conjugated Cycles

⏱️ Save ~40 seconds

Hückel’s rule requires (4n + 2) delocalized π electrons in a planar conjugated ring. Count π electrons for each: i (10, n=2) ✓; ii (6, n=1) ✓; iii (4, 4n anti-aromatic) ✗; iv (4, 4n anti-aromatic) ✗; v (2, n=0) ✓; vi (8, non-planar tub) ✗; vii (14, n=3) ✓. Exactly 4 species obey Hückel’s rule in 15 seconds!

1 Check i (Naphthalene): 10 π electrons (4n+2 with n=2) ⟶ Aromatic (Obey).

2 Check ii (Cyclopentadienyl anion): 4 from double bonds + 2 from lone pair = 6 π electrons (n=1) ⟶ Aromatic (Obey).

3 Check iii (Cyclobutadiene): 4 π electrons (4n system) ⟶ Anti-aromatic (Does NOT obey).

4 Check iv (Cyclopropenyl anion): 2 from double bond + 2 from lone pair = 4 π electrons (4n system) ⟶ Anti-aromatic (Does NOT obey).

5 Check v (Cyclopropenyl cation): 2 π electrons (4n+2 with n=0) ⟶ Aromatic (Obey).

6 Check vi (Cyclooctatetraene): 8 π electrons, adopts non-planar tub conformation ⟶ Non-aromatic (Does NOT obey).

7 Check vii (Anthracene): 14 π electrons (4n+2 with n=3) ⟶ Aromatic (Obey).

8 Total qualifying species = 4 (Option 2).

🛡️

Why You Can 100% Trust This Shortcut: Classical Hückel’s Rule criteria for aromaticity in NCERT Organic Chemistry.

📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Criteria for Obeying Hückel’s Rule

For a compound to obey Hückel’s rule of aromaticity, it must satisfy three structural criteria: (a) cyclic and planar ring system, (b) complete delocalization of π electrons across the ring, and (c) contain (4n + 2) π electrons where n = 0, 1, 2, 3...

\text{Hückel's Formula: } N_\pi = 4n + 2 \quad (n = 0, 1, 2, 3, \dots)

Step 2

Evaluation of Benzenoid Fused Arenes

Naphthalene (i) has 5 conjugated double bonds = 10 π electrons (4n+2 with n=2). Anthracene (vii) has 7 conjugated double bonds = 14 π electrons (4n+2 with n=3). Both are planar, fully conjugated, and aromatic:

\text{Naphthalene (i): } 10\pi\ (n=2), \quad \text{Anthracene (vii): } 14\pi\ (n=3) \implies \text{Both Obey}

Step 3

Evaluation of Charged Carbocycles

Cyclopentadienyl anion (ii) has two double bonds (4 e⁻) and one localized lone pair in a p-orbital (2 e⁻) = 6 π electrons (n=1, aromatic). Cyclopropenyl cation (v) has one double bond (2 e⁻) and a vacant p-orbital = 2 π electrons (n=0, aromatic):

\text{Cyclopentadienyl anion (ii): } 6\pi\ (n=1), \quad \text{Cyclopropenyl cation (v): } 2\pi\ (n=0) \implies \text{Both Obey}

Step 4

Disqualification of Non-Aromatic and Anti-Aromatic Species

Cyclobutadiene (iii) has 4 π electrons (4n, anti-aromatic). Cyclopropenyl anion (iv) has 4 π electrons (4n, anti-aromatic). Cyclooctatetraene (vi) has 8 π electrons and adopts a non-planar tub conformation (non-aromatic). None of these three obey Hückel’s rule:

\text{Species iii, iv, vi: Do not obey Hückel's rule} \implies \text{Total Obeying} = 4

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan

1 (1)

✗ Incorrect

Verdict & Scientific Reason:

Overcounts by including cyclooctatetraene or an anti-aromatic ring.

⚠️

Student Fallacy (Why candidates pick this trap): Candidate incorrectly counted COT (8π) as aromatic.

2 (2)

✓ 100% Correct

Verdict & Scientific Reason:

Accurate: Exactly 4 species obey Hückel’s rule (i: 10π, ii: 6π, v: 2π, vii: 14π).

💡

Why this is airtight: None. Candidate correctly applied (4n + 2) and planarity requirements.

3 (3)

✗ Incorrect

Verdict & Scientific Reason:

Includes anti-aromatic 4n systems (cyclobutadiene and cyclopropenyl anion).

⚠️

Student Fallacy (Why candidates pick this trap): Candidate counted 4n π electron systems as obeying Hückel’s rule.

4 (4)

✗ Incorrect

Verdict & Scientific Reason:

Counted only fused benzenoids and missed charged aromatic ions.

⚠️

Student Fallacy (Why candidates pick this trap): Candidate did not recognize charged species (cyclopentadienyl anion, cyclopropenyl cation) as aromatic.

⚠️

NTA Trap Alert: Counting π-Electrons in Carbanions and Carbocations

In cyclopropenyl anion, the lone pair adds 2 electrons to the double bond, giving 4π electrons (4n, anti-aromatic). In cyclopropenyl cation, the vacant p-orbital has 0 electrons, giving 2π electrons (4n+2 with n=0, aromatic). Don’t confuse anion and cation!

🛡️ How to avoid the -1 mark: Carbanion carbon in conjugated ring contributes 2 π electrons; carbocation carbon with vacant p-orbital contributes 0.

📖

Core NEET Syllabus Standard

National Eligibility cum Entrance Test (NEET UG) · Hydrocarbons Standard Benchmark

Core Scientific Principle Tested:

"A planar, cyclic, fully conjugated system possessing (4n + 2) π electrons exhibits exceptional aromatic stability."

Syllabus Focus: Aromaticity – Hückel’s Rule

Preserved in Rationalized Curriculum Syllabus & Academic Standards ↗

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NEET 2023 Chemistry Question 90 Solution

Question

The 30-Second Exam Hall Shortcut: ⚡ Hückel’s Magic Numbers: 2, 6, 10, 14 π Electrons in Planar Conjugated Cycles

Step-by-Step Rigorous Workflow & Mathematical Proof

Criteria for Obeying Hückel’s Rule

Evaluation of Benzenoid Fused Arenes

Evaluation of Charged Carbocycles

Disqualification of Non-Aromatic and Anti-Aromatic Species

360° Option Elimination Engine Key Feature

NTA Trap Alert: Counting π-Electrons in Carbanions and Carbocations

Core NEET Syllabus Standard

Ready to attempt under real exam pressure?

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