NEET 2023 Chemistry Question 81 Solution
Question
The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm⁻¹ cm⁻¹ and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of cell constant is -
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The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm⁻¹ cm⁻¹ and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of cell constant is -
Cell constant G* is simply the product of conductivity (κ) and resistance (R): G* = κ · R. Compute 0.0210 × 60 = 1.26 cm⁻¹ in under 5 seconds! The concentration is distractor data.
The cell constant G* represents the geometric ratio of electrode separation (l) to electrode surface area (A):
Conductivity κ (specific conductance) is defined as the reciprocal of resistivity ρ:
Substitute the given conductivity κ = 0.0210 Ω⁻¹ cm⁻¹ and resistance R = 60 Ω:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Inverted calculation artifact from dividing resistance by incorrect factors.
Arithmetic calculation error.
Erroneous calculation involving centimolar concentration factor.
Accurate: G* = κ × R = 0.0210 × 60 = 1.26 cm⁻¹.
The phrase "centimolar solution of KCl" is provided as realistic contextual data, but it is completely superfluous for calculating the cell constant. Students often waste time trying to compute molar conductivity Λm = (1000 · κ)/M.
"Cell constant G* is an intrinsic geometric property of a conductance cell given by G* = κ · R."
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