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Q.54 Chemistry ⭐ 360° Option Elimination Active
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NEET 2021 Chemistry Question 54 Solution

Topic: Structure of Atom · Official NTA Booklet Code M1
NEET 2021 Chemistry Question 54: Wave Nature of Light: Frequency to Wavelength Conversion

Question

A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is: [speed of light, c = 3.0×10⁸ m s⁻¹]

✓
Verified Against NTA Final Answer Key
Option (1) : 219.3 m
📚 Structure of Atom Easy
📋 Given Parameters & Problem Setup
Broadcasting Frequency (ν) 1,368 kHz = 1,368 × 10^3 Hz
Speed of Light (c) 3.0 × 10^8 m/s
⚡

The 30-Second Exam Hall Shortcut: ⚡ Fast Wave Formula: λ = c / ν

⏱️ Save ~20 seconds

λ=3.0×1081368×103=300,0001368=219.298 m≈219.3 m\lambda = \frac{3.0 \times 10^8}{1368 \times 10^3} = \frac{300,000}{1368} = 219.298\text{ m} \approx 219.3\text{ m}! Direct 10-second division matching Option (1)!

1 Convert frequency to SI base units: ν=1368 kHz=1.368×106 s−1\nu = 1368\text{ kHz} = 1.368 \times 10^6\text{ s}^{-1}.
2 Wave equation: c=νλ  ⟹  λ=cνc = \nu \lambda \implies \lambda = \frac{c}{\nu}.
3 Substitute: λ=3.0×108 m/s1368×103 s−1=300013.68=219.298 m\lambda = \frac{3.0 \times 10^8\text{ m/s}}{1368 \times 10^3\text{ s}^{-1}} = \frac{3000}{13.68} = 219.298\text{ m}.
4 Round to 4 significant figures: 219.3 m219.3\text{ m}.
5 Match Option (1).
🛡️
Why You Can 100% Trust This Shortcut: Canonical wave mechanics velocity-frequency-wavelength relation (c=νλc = \nu \lambda).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Stating the Fundamental Wave Equation

For any electromagnetic radiation propagating in vacuum or air, the speed of light cc is related to frequency ν\nu and wavelength λ\lambda by:

c=ν⋅λ  ⟹  λ=cνc = \nu \cdot \lambda \implies \lambda = \frac{c}{\nu}
Step 2

Converting Frequency to Standard SI Units

The given frequency is in kilohertz (1 kHz=103 Hz=103 s−11\text{ kHz} = 10^3\text{ Hz} = 10^3\text{ s}^{-1}):

ν=1368 kHz=1368×103 Hz=1.368×106 s−1\nu = 1368\text{ kHz} = 1368 \times 10^3\text{ Hz} = 1.368 \times 10^6\text{ s}^{-1}
Step 3

Computing the Wavelength

Substitute c=3.0×108 m/sc = 3.0 \times 10^8\text{ m/s} and ν=1.368×106 s−1\nu = 1.368 \times 10^6\text{ s}^{-1}:

λ=3.0×108 m/s1.368×106 s−1=3001.368 m=219.298 m≈219.3 m\lambda = \frac{3.0 \times 10^8\text{ m/s}}{1.368 \times 10^6\text{ s}^{-1}} = \frac{300}{1.368}\text{ m} = 219.298\text{ m} \approx 219.3\text{ m}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✓ 100% Correct
Verdict & Scientific Reason:

Exact wavelength: 3.0×108/(1368×103)=219.298 m≈219.3 m3.0 \times 10^8 / (1368 \times 10^3) = 219.298\text{ m} \approx 219.3\text{ m}.

💡
Why this is airtight: None; precise arithmetic calculation.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Truncates without rounding up (219.298219.298 rounds up to 219.3219.3, not 219.2219.2).

⚠️
Student Fallacy (Why candidates pick this trap): Truncation error rather than proper mathematical rounding.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Off by a factor of 10 from mishandling powers of ten (108/10310^8 / 10^3).

⚠️
Student Fallacy (Why candidates pick this trap): Order of magnitude exponent subtraction error.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Gross unit mismatch (centimeters instead of meters).

⚠️
Student Fallacy (Why candidates pick this trap): Unit confusion.
⚠️

NTA Trap Alert: Rounding vs. Truncation Trap (Option 1 vs. Option 2)

The raw division gives 219.298 m219.298\text{ m}. Candidates who truncate to 4 digits get 219.2 m219.2\text{ m} (Option 2). Applying correct significant figure rounding rules to the next digit (9) requires rounding UP to 219.3 m219.3\text{ m} (Option 1).

🛡️ How to avoid the -1 mark: Since 0.298>0.250.298 > 0.25, round UP to 0.30.3: 219.3 m219.3\text{ m}.
📖

Core NEET Syllabus Standard

NCERT Chemistry · Structure of Atom Standard Benchmark
Core Scientific Principle Tested:

"The wavelength of electromagnetic radiation is λ=c/ν\lambda = c / \nu."

Syllabus Focus: Wave Nature of Electromagnetic Radiation
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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