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Q.175 Physics ⭐ 360° Option Elimination Active
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NEET 2020 Physics Question 175 Solution

Topic: Dual Nature of Radiation and Matter · Official NTA Booklet Code E1
NEET 2020 Physics Question 175: Accelerating Potential for an Electron from de Broglie Wavelength

Question

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10⁻² nm, the potential difference is:

✓
Verified Against NTA Final Answer Key
Option (4) : 10^4 V
📚 Dual Nature of Radiation and Matter Medium
📋 Given Parameters & Problem Setup
de Broglie Wavelength lambda = 1.227 × 10^-2 nm
Standard Formula for Electron lambda = 1.227 / sqrt(V) nm
⚡

The 30-Second Exam Hall Shortcut: ⚡ "lambda = 1.227 / sqrt(V) nm => 1.227 × 10^-2 = 1.227 / sqrt(V) => sqrt(V) = 100 => V = 100^2 = 10000 V = 10^4 V!"

⏱️ 20 seconds

For an electron accelerated through potential difference V, de Broglie wavelength is lambda = 1.227 / sqrt(V) nm. Equating to 1.227 × 10^-2 nm gives sqrt(V) = 1 / 10^-2 = 100 => V = 100^2 = 10000 V = 10^4 V. Don't forget to square 100! Mark Option (4) in 5 seconds.

1 Formula: λ=1.227V nm\lambda = \frac{1.227}{\sqrt{V}}\text{ nm}.
2 Substitute given wavelength: 1.227×10−2 nm=1.227V nm1.227 \times 10^{-2}\text{ nm} = \frac{1.227}{\sqrt{V}}\text{ nm}.
3 Cancel 1.227: V=110−2=100\sqrt{V} = \frac{1}{10^{-2}} = 100.
4 Square to find potential: V=(100)2=104 VV = (100)^2 = 10^4\text{ V}.
5 Select Option (4).
🛡️
Why You Can 100% Trust This Shortcut: NCERT Physics · Dual Nature of Radiation and Matter (de Broglie Wavelength of an Electron)
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formula for de Broglie Wavelength of Accelerated Electron

An electron of mass mm and charge ee accelerated from rest through potential difference VV acquires kinetic energy K=eVK = eV. Its de Broglie wavelength is: λ=hp=h2meV\lambda = \frac{h}{p} = \frac{h}{\sqrt{2m e V}}.

Step 2

Substitute Universal Constants

Substituting h=6.626×10−34 J sh = 6.626 \times 10^{-34}\text{ J s}, m=9.1×10−31 kgm = 9.1 \times 10^{-31}\text{ kg}, and e=1.6×10−19 Ce = 1.6 \times 10^{-19}\text{ C} gives the standard compact formula: λ=1.227V nm=12.27V A˚\lambda = \frac{1.227}{\sqrt{V}}\text{ nm} = \frac{12.27}{\sqrt{V}}\text{ \AA}.

Step 3

Equate and Solve for Potential V

Given λ=1.227×10−2 nm\lambda = 1.227 \times 10^{-2}\text{ nm}: 1.227×10−2=1.227V1.227 \times 10^{-2} = \frac{1.227}{\sqrt{V}} Divide both sides by 1.2271.227: 10−2=1V  ⟹  V=102=10010^{-2} = \frac{1}{\sqrt{V}} \implies \sqrt{V} = 10^2 = 100. Squaring both sides: V=1002=10000 V=104 VV = 100^2 = 10000\text{ V} = 10^4\text{ V}.

Step 4

Conclude and Verify

Matches Option 4.

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; for V = 10 V, lambda ≈ 0.388 nm.

⚠️
Student Fallacy (Why candidates pick this trap): Random power-of-ten mismatch.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; forgets to square sqrt(V) = 100, answering 100 V instead of 10000 V.

⚠️
Student Fallacy (Why candidates pick this trap): Classic error of forgetting to square sqrt(V).
3 C
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; corresponds to sqrt(V) ≈ 31.6 V.

⚠️
Student Fallacy (Why candidates pick this trap): Arithmetic miscalculation.
4 D
✓ 100% Correct
Verdict & Scientific Reason:

Accurate value; sqrt(V) = 100 => V = 100^2 = 10^4 V.

💡
Why this is airtight: None; remembers to square the square-root term.
⚠️

NTA Trap Alert: Squaring the Square Root

Students frequently solve for sqrt(V) = 100 and immediately mark 100 V (10^2 V, Option B). The potential is V, so you MUST square it: (100)^2 = 10^4 V.

🛡️ How to avoid the -1 mark: Always write: V = (sqrt(V))^2 = 100^2 = 10^4 V.
📖

Core NEET Syllabus Standard

Physics · Dual Nature of Radiation and Matter Standard Benchmark
Core Scientific Principle Tested:

""

Syllabus Focus: Accelerating Potential for an Electron from de Broglie Wavelength
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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