NEET 2026 Botany Question 133 Solution
Question
Length of the stem at time O is 20 cm. The arithmetic growth rate is 30 cm per day. What is the length of the stem at the end of the 7' day?
Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.
Length of the stem at time O is 20 cm. The arithmetic growth rate is 30 cm per day. What is the length of the stem at the end of the 7' day?
L_t = L₀ + rt -> 20 + (30 × 7) = 230 cm!
In arithmetic growth, following mitotic cell division, only one daughter cell continues to divide while the other differentiates and matures. This produces a constant linear elongation over time, mathematically expressed by a straight line graph ().
Given: , , and .
Add the growth increment to the initial stem length:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect. Adds 20 + 30 for only 1 day of growth ().
Incorrect. Subtracts initial length (210 - 20 = 190) or applies incorrect arithmetic.
100% mathematically and conceptually accurate: .
Incorrect. Doubled the correct answer or misapplied geometric growth.
Students calculate and either hunt for 210 or misread options, forgetting that the plant ALREADY measured 20 cm at .
"Arithmetic growth is expressed mathematically as , plotting a linear curve with slope equal to growth rate r."
Test your speed and accuracy in the authentic 180-minute timed NTA simulator.
Spotted a mistake in this solution? Report an error (support@mycompetitiveexams.com)
Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.