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Match List I with List II. List I: A. RNA polymerase III; B. Termination of transcription; C. Splicing of Exons; D. TATA box. List II: I. snRNPs; II. Promotor; III. Rho factor; IV. SnRNAs, tRNA. Choose the correct answer from the options given below:
RNA Pol III = tRNA and snRNAs (IV); Termination = Rho factor (III); Splicing = snRNPs / spliceosome (I); TATA box = Core promoter element (II)! Match: A-IV, B-III, C-I, D-II!
In eukaryotes, there are at least three RNA polymerases in the nucleus. RNA polymerase I transcribes rRNAs (28S, 18S, and 5.8S). RNA polymerase II transcribes precursor of mRNA (hnRNA). RNA polymerase III is responsible for transcription of tRNA, 5S rRNA, and snRNAs (small nuclear RNAs) (A -> IV).
- In bacteria, RNA polymerase associates transiently with termination factor (, rho factor) to terminate transcription (B -> III). - Splicing involves removal of introns and joining of exons, catalyzed by the spliceosome formed of small nuclear ribonucleoproteins (snRNPs) (C -> I). - The TATA box is a conserved hexanucleotide sequence found within the core promoter region of eukaryotic genes where transcription factors bind (D -> II).
A-IV, B-III, C-I, D-II corresponds to Option (2).
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Mismatches RNA polymerase III with Rho factor.
Accurately pairs all transcriptional components and processing machinery with their molecular counterparts.
Mismatches RNA polymerase III with promoter.
Mismatches RNA polymerase III with Rho factor.
Confusing products of RNA Polymerase II (hnRNA/mRNA) with RNA Polymerase III (tRNA, 5S rRNA, snRNA).
"The RNA polymerase III is responsible for transcription of tRNA, 5srRNA, and snRNAs (small nuclear RNAs). The RNA polymerase associates transiently with termination-factor (rho) to terminate transcription. Splicing removes introns and joins exons."
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