MyCompetitiveExams Logo MyCompetitiveExams
MyCompetitiveExams Logo MyCompetitiveExams
Search 1,140+ Questions
Chapters, formulas, speed tricks
→
⚡ Brahmastra NEET 2027
720 MARKS

Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.

Launch Brahmastra 2027 Test →
Start Practice →
100% Free · No Login Required
Q.38 Physics · Section B ⭐ 360° Option Elimination Active
Vault ↗

NEET 2024 Physics Question 38 Solution

Topic: Oscillations · Official NTA Booklet Code T1
NEET 2024 Physics Question 38: Time Period Variation with Mass and Length of a Simple Pendulum

Question

If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is x/2 times its original time period. Then the value of x is:

✓
Verified Against NTA Final Answer Key
Option (4) : √2
📚 Oscillations Easy
📋 Given Parameters & Problem Setup
Mass of bob change Tripled (3m)
Length of pendulum change Halved (L / 2)
New time period expression T’ = (x / 2) T
⚡

The 30-Second Exam Hall Shortcut: ⚡ Mass Independence & Length Scaling Hack

⏱️ Save ~40 seconds

Mass of bob has ZERO effect on pendulum period (T = 2π√(L/g))! Length halved -> T’ = T / √2 = (√2 / 2) T -> x = √2!

1 Simple pendulum period: T = 2π√(L/g). Mass of the bob does NOT enter the equation!
2 Tripling mass has 0 effect.
3 Halving length: L’ = L / 2 => T’ = 2π√(L / 2g) = T / √2.
4 Match with given form: T’ = (x / 2) T => 1 / √2 = x / 2 => x = 2 / √2 = √2.
5 Option (4) in 5 seconds!
🛡️
Why You Can 100% Trust This Shortcut: Simple Pendulum Equation of Motion (Time period T = 2π√(L/g) is independent of bob mass).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formula for Time Period of Simple Pendulum

For small angular displacements, the time period T of a simple pendulum of length L and bob mass m oscillating under gravity g is given by:

T=2πLgT = 2\pi \sqrt{\frac{L}{g}}
Step 2

Independence of Bob Mass

Notice that the mass m of the bob does not appear in the formula. Restoring torque and rotational inertia both scale linearly with m, so mass cancels out identically. Therefore, tripling the mass does not change the time period at all.

∂T∂m=0  ⟹  T is independent of mass\frac{\partial T}{\partial m} = 0 \implies T \text{ is independent of mass}
Step 3

Effect of Halving the Length

The length is made half its original length: L’ = L / 2. The new time period T’ is:

T′=2πL/2g=12(2πLg)=T2T' = 2\pi \sqrt{\frac{L/2}{g}} = \frac{1}{\sqrt{2}} \left(2\pi \sqrt{\frac{L}{g}}\right) = \frac{T}{\sqrt{2}}
Step 4

Solving for Parameter x

We are given that T’ = (x / 2) T. Equating the two expressions:

x2T=12T  ⟹  x2=12  ⟹  x=22=2\frac{x}{2} T = \frac{1}{\sqrt{2}} T \implies \frac{x}{2} = \frac{1}{\sqrt{2}} \implies x = \frac{2}{\sqrt{2}} = \sqrt{2}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

Includes the factor of 3 from mass tripling.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming period is proportional to √mass.
2 (2)
✗ Incorrect
Verdict & Scientific Reason:

Incorrect algebra.

⚠️
Student Fallacy (Why candidates pick this trap): Squaring instead of square rooting.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Uses the mass factor 3 instead of the length factor.

⚠️
Student Fallacy (Why candidates pick this trap): Thinking T depends on mass.
4 (4)
✓ 100% Correct
Verdict & Scientific Reason:

Exact result: 1/√2 = x/2 -> x = √2.

💡
Why this is airtight: None.
⚠️

NTA Trap Alert: Including the Bob Mass in Pendulum Period

NTA includes √3 and 2√3 to bait students who mistakenly recall spring-mass formula T = 2π√(m/k) instead of pendulum formula T = 2π√(L/g).

🛡️ How to avoid the -1 mark: Pendulum period depends ONLY on Length and Gravity, NEVER on Mass!
📖

Core NEET Syllabus Standard

Physics Core Oscillations · Oscillations Standard Benchmark
Core Scientific Principle Tested:

"The period of a simple pendulum is T = 2π√(L/g), independent of mass and amplitude (for small angles)."

Syllabus Focus: The Simple Pendulum
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
Mass doesn’t matter for a pendulum string: Length cut in half makes x equal √2 king!

Ready to attempt under real exam pressure?

Test your speed and accuracy in the authentic 200-minute timed NTA simulator.

Launch NEET 2024 CBT Test →

Spotted a mistake in this solution? Report an error (support@mycompetitiveexams.com)

⚖️ Legal & Fair Dealing Notice: Sourced from publicly released NEET 2024 question papers and NEET answer keys for private study, research, and non-commercial educational practice under Fair Dealing (Section 52(1)(a) of the Indian Copyright Act, 1957). Not affiliated with or endorsed by NTA or NMC.

Solve 4 NEET Questions a Day — One per Subject

Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.