MyCompetitiveExams Logo MyCompetitiveExams
MyCompetitiveExams Logo MyCompetitiveExams
Search 1,140+ Questions
Chapters, formulas, speed tricks
→
⚡ Brahmastra NEET 2027
720 MARKS

Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.

Launch Brahmastra 2027 Test →
Start Practice →
100% Free · No Login Required
Q.37 Physics · Section B ⭐ 360° Option Elimination Active
Vault ↗

NEET 2024 Physics Question 37 Solution

Topic: Current Electricity · Official NTA Booklet Code T1
NEET 2024 Physics Question 37: Ratio of Power Outputs for Heaters in Series versus Parallel

Question

Two heaters A and B have power rating of 1 kW and 2 kW, respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:

✓
Verified Against NTA Final Answer Key
Option (4) : 2 : 9
📚 Current Electricity Easy
📋 Given Parameters & Problem Setup
Heater A power rating P_A = 1 kW
Heater B power rating P_B = 2 kW
Source voltage Same fixed power source V
⚡

The 30-Second Exam Hall Shortcut: ⚡ Power Reciprocal Product Rule

⏱️ Save ~45 seconds

Series power: 1/P_s = 1/1 + 1/2 = 3/2 -> P_s = 2/3 kW. Parallel power: P_p = 1 + 2 = 3 kW. Ratio P_s / P_p = (2/3) / 3 = 2 : 9!

1 In series across fixed voltage V: 1 / P_series = 1 / P_A + 1 / P_B = 1 / 1 + 1 / 2 = 3/2 => P_series = 2/3 kW.
2 In parallel across fixed voltage V: P_parallel = P_A + P_B = 1 + 2 = 3 kW.
3 Ratio of power outputs: P_series / P_parallel = (2/3) / 3 = 2 / 9 = 2 : 9.
4 Option (4) in 10 seconds!
🛡️
Why You Can 100% Trust This Shortcut: Power Dissipation Formula for Fixed Voltage Source (P_parallel = Σ P_i, 1/P_series = Σ 1/P_i).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Resistances of Heaters from Rated Power

For a heater designed for rated voltage V, power is P = V² / R, which gives resistance R = V² / P:

RA=V2PA=V21 kW,RB=V2PB=V22 kW=RA2R_A = \frac{V^2}{P_A} = \frac{V^2}{1\,\text{kW}}, \quad R_B = \frac{V^2}{P_B} = \frac{V^2}{2\,\text{kW}} = \frac{R_A}{2}
Step 2

Case 1: Heaters in Series

When connected in series across the same fixed voltage source V, the total equivalent resistance is:

Rseries=RA+RB=RA+RA2=32RAR_{series} = R_A + R_B = R_A + \frac{R_A}{2} = \frac{3}{2} R_A
Step 3

Power Output in Series

The power delivered in the series configuration is:

Pseries=V2Rseries=V232RA=23V2RA=23PA=23 kWP_{series} = \frac{V^2}{R_{series}} = \frac{V^2}{\frac{3}{2} R_A} = \frac{2}{3} \frac{V^2}{R_A} = \frac{2}{3} P_A = \frac{2}{3}\,\text{kW}
Step 4

Case 2: Heaters in Parallel

When connected in parallel across the same fixed voltage V, each heater has the full source voltage across it. Power outputs add directly:

Pparallel=PA+PB=1 kW+2 kW=3 kWP_{parallel} = P_A + P_B = 1\,\text{kW} + 2\,\text{kW} = 3\,\text{kW}
Step 5

Ratio of Power Outputs

Taking the ratio of the series power to parallel power:

PseriesPparallel=2/3 kW3 kW=29  ⟹  Pseries:Pparallel=2:9\frac{P_{series}}{P_{parallel}} = \frac{2/3\,\text{kW}}{3\,\text{kW}} = \frac{2}{9} \implies P_{series} : P_{parallel} = 2 : 9
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

This is the ratio of the individual heater powers (1 kW : 2 kW).

⚠️
Student Fallacy (Why candidates pick this trap): Confusing individual power ratings with series-to-parallel combination ratio.
2 (2)
✗ Incorrect
Verdict & Scientific Reason:

Represents only P_series in kW, forgetting to divide by P_parallel = 3 kW.

⚠️
Student Fallacy (Why candidates pick this trap): Stopping at P_series = 2/3.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Physical impossibility; parallel power is always much greater than series power.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming power is conserved regardless of circuit configuration.
4 (4)
✓ 100% Correct
Verdict & Scientific Reason:

Exact ratio: (2/3) / 3 = 2/9.

💡
Why this is airtight: None.
⚠️

NTA Trap Alert: Power Formulas Inversion Trap

Students frequently remember "P = I²R so series adds", forgetting that current I is drastically reduced in series when connected to a fixed VOLTAGE source.

🛡️ How to avoid the -1 mark: For fixed voltage V: In parallel, powers add directly (P_p = P1 + P2); in series, reciprocal powers add (1/P_s = 1/P1 + 1/P2)!
📖

Core NEET Syllabus Standard

Physics Core Electrodynamics · Current Electricity Standard Benchmark
Core Scientific Principle Tested:

"Across a constant voltage source, P_parallel = P1 + P2 and 1/P_series = 1/P1 + 1/P2."

Syllabus Focus: Electric Power and Heating Effects of Current
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
Series adds reciprocals (2/3); Parallel adds direct (3) -> Ratio is 2 to 9!

Ready to attempt under real exam pressure?

Test your speed and accuracy in the authentic 200-minute timed NTA simulator.

Launch NEET 2024 CBT Test →

Spotted a mistake in this solution? Report an error (support@mycompetitiveexams.com)

⚖️ Legal & Fair Dealing Notice: Sourced from publicly released NEET 2024 question papers and NEET answer keys for private study, research, and non-commercial educational practice under Fair Dealing (Section 52(1)(a) of the Indian Copyright Act, 1957). Not affiliated with or endorsed by NTA or NMC.

Solve 4 NEET Questions a Day — One per Subject

Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.