NEET 2023 Physics Question 18 Solution
Question
Resistance of a carbon resistor determined from colour codes is (22000 ± 5%) Ω. The colour of third band must be:
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Resistance of a carbon resistor determined from colour codes is (22000 ± 5%) Ω. The colour of third band must be:
22000 Ω is 22 × 10³ Ω; the 3rd band represents the power of 10 (10³); in B-B-R-O-Y, 3 corresponds to Orange!
Standard 4-band carbon resistors encode resistance as R = (AB × 10^C ± D%) Ω, where A and B are the first two significant figures, C is the decimal multiplier, and D is the tolerance percentage:
Comparing with the standard colour-code format:
Using the canonical mnemonic "B B R O Y of Great Britain has Very Good Wife":
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Yellow corresponds to digit 4 (multiplier 10⁴ = 220,000 Ω).
Red corresponds to digit 2 (multiplier 10² = 2200 Ω).
Green corresponds to digit 5 (multiplier 10⁵).
Accurate colour: exponent 3 corresponds to Orange in the BB ROY colour code.
The number 22000 has 3 zeroes, meaning the multiplier is 10³, which is Orange. Students who count all zeroes plus the significant digits get confused and pick Yellow.
"First two bands give significant digits, third band gives power of ten multiplier, fourth band gives tolerance."
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