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Q.134 Botany ⭐ 360° Option Elimination Active
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NEET 2025 Botany Question 134 Solution

Topic: Molecular Basis of Inheritance · Official NTA Booklet Code 45
NEET 2025 Botany Question 134: Historical Genetic Experiments and Chromatin Packing States

Question

Match List I with List II. List I: A. Alfred Hershey and Martha Chase; B. Euchromatin; C. Frederick Griffith; D. Heterochromatin. List II: I. Streptococcus pneumoniae; II. Densely packed and dark-stained; III. Loosely packed and light-stained; IV. DNA as genetic material confirmation. Choose the correct answer from the options given below:

✓
Verified Against NTA Final Answer Key
Option (3) : A-IV, B-III, C-I, D-II
📚 Molecular Basis of Inheritance Easy
📋 Given Parameters & Problem Setup
List-I A. Alfred Hershey and Martha Chase, B. Euchromatin, C. Frederick Griffith, D. Heterochromatin
List-II I. Streptococcus pneumoniae, II. Densely packed and dark-stained, III. Loosely packed and light-stained, IV. DNA as genetic material confirmation
⚡

The 30-Second Exam Hall Shortcut: ⚡ Molecular Genetics Match Fingerprint

⏱️ Save ~30 seconds

Hershey-Chase = DNA confirmation using ³²P/³⁵S (IV); Euchromatin = Loosely packed, light-stained, active (III); Griffith = Transformation in Streptococcus pneumoniae (I); Heterochromatin = Densely packed, dark-stained, inactive (II)!

1 Match each scientist and chromatin structure instantly:
2 - Alfred Hershey and Martha Chase (1952): Unequivocal confirmation that DNA is the genetic material using bacteriophage T2 (A -> IV).
3 - Euchromatin: Loosely coiled region of chromatin, stains light, transcriptionally active (B -> III).
4 - Frederick Griffith (1928): Transformation experiments with Streptococcus pneumoniae (Diplococcus) in mice (C -> I).
5 - Heterochromatin: Densely packed chromatin, stains dark, transcriptionally inactive (D -> II).
6 Combined code: A-IV, B-III, C-I, D-II -> Option (3)!
7 Solved in under 10 seconds!
🛡️
Why You Can 100% Trust This Shortcut: DNA Replication Machinery & Okazaki Fragments (NCERT Biology · Molecular Basis of Inheritance: DNA polymerase continuous vs discontinuous synthesis).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Review of the Scientists and Their Discoveries

Foundational experiments in the discovery and proof of the genetic material:

  • • Frederick Griffith (1928): Conducted experiments with *Streptococcus pneumoniae* (bacteria responsible for pneumonia). Discovered that non-virulent R strain was transformed into virulent S strain by heat-killed S bacteria (Transforming Principle). Hence, C matches I.
  • • Alfred Hershey and Martha Chase (1952): Provided the unequivocal, definitive proof that DNA is the genetic material. Worked with bacteriophage T2 and *E. coli*, labeling viral DNA with ³²P and viral protein capsid with ³⁵S. Hence, A matches IV.
Step 2

Chromatin Organization in Eukaryotic Nucleus

Cytological differentiation of interphase chromatin:

  • • Euchromatin: In a typical nucleus, some regions of chromatin are loosely packed and stain light with basic dyes. Euchromatin is transcriptionally active. Hence, B matches III.
  • • Heterochromatin: The chromatin regions that are more densely packed and stain dark are called heterochromatin. Heterochromatin is transcriptionally inactive. Hence, D matches II.
Step 3

Assembling the Matching Matrix

Combining the verified pairings:

  • • A -> IV (DNA as genetic material confirmation)
  • • B -> III (Loosely packed and light-stained)
  • • C -> I (Streptococcus pneumoniae)
  • • D -> II (Densely packed and dark-stained)
Step 4

Conclusion

The unambiguous combination is A-IV, B-III, C-I, D-II, matching Option (3).

Matching: A-IV,  B-III,  C-I,  D-II\text{Matching: } A\text{-IV}, \; B\text{-III}, \; C\text{-I}, \; D\text{-II}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Assigns densely packed to Hershey-Chase and DNA confirmation to euchromatin.

⚠️
Student Fallacy (Why candidates pick this trap): Scrambling historical experiments with structural terms.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Inverts the staining and packing states of euchromatin (III) and heterochromatin (II).

⚠️
Student Fallacy (Why candidates pick this trap): Confusing euchromatin (light/loose) with heterochromatin (dark/dense).
3 C
✓ 100% Correct
Verdict & Scientific Reason:

100% correct. Accurately links both landmark genetic experiments and the two cytological chromatin states.

💡
Why this is airtight: None; textbook mastery.
4 D
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Scrambles scientists and chromatin properties completely.

⚠️
Student Fallacy (Why candidates pick this trap): Random guessing.
⚠️

NTA Trap Alert: Euchromatin vs Heterochromatin Inversion

A frequent stumbling block: EUchromatin is "TRUE" chromatin -> loose, light-staining, transcriptionally active. HETEROchromatin is densely packed, dark-staining, transcriptionally silent.

🛡️ How to avoid the -1 mark: Eu = "Good/Active" (Loose & Light); Hetero = "Heavy" (Dense & Dark).
📖

Core NEET Syllabus Standard

NEET Biology Core Syllabus · Molecular Basis of Inheritance Standard Benchmark
Core Scientific Principle Tested:

"Hershey-Chase proved DNA is the genetic material; Griffith used Streptococcus; euchromatin is light/loose, and heterochromatin is dark/dense."

Syllabus Focus: The Genetic Material & Packaging of DNA Helix
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
H-C confirms DNA (IV), Griffith did Strep (I), Eu is Light (III), Hetero is Dark (II)!

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