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Q.17 Physics ⭐ 360° Option Elimination Active
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NEET 2021 Physics Question 17 Solution

Topic: Electromagnetic Waves · Official NTA Booklet Code M1
NEET 2021 Physics Question 17: Polarization and Propagation of Plane EM Waves: Poynting Vector Direction

Question

For a plane electromagnetic wave propagating in x-direction, which one of the following combination gives the correct possible directions for electric field (E) and magnetic field (B) respectively?

✓
Verified Against NTA Final Answer Key
Option (2) : (-j + k), (-j - k)
📚 Electromagnetic Waves Medium
📋 Given Parameters & Problem Setup
Wave Direction Positive x-direction (+i)
Condition 1 E ⟂ B (E · B = 0)
Condition 2 Poynting vector E × B must point along +i
⚡

The 30-Second Exam Hall Shortcut: ⚡ Cross Product Filter: E × B must be along +i

⏱️ Save ~25 seconds

The wave propagates along +x+x (i^\hat{i}), so E⃗×B⃗\vec{E} \times \vec{B} must point along +i^+\hat{i}, and E⃗⋅B⃗=0\vec{E} \cdot \vec{B} = 0. In Option (2): (−j^+k^)×(−j^−k^)=j^×k^−k^×j^=i^−(−i^)=+2i^(-\hat{j} + \hat{k}) \times (-\hat{j} - \hat{k}) = \hat{j}\times\hat{k} - \hat{k}\times\hat{j} = \hat{i} - (-\hat{i}) = +2\hat{i}! In all other options, E⃗\vec{E} and B⃗\vec{B} are parallel or antiparallel (cross product = 0)! Select Option (2)!

1 Universal EM wave rule: Wave propagation direction is given by the unit vector along E⃗×B⃗\vec{E} \times \vec{B}.
2 Here, propagation is along +i^+\hat{i}. Thus, E⃗×B⃗=Ci^\vec{E} \times \vec{B} = C \hat{i} with C>0C > 0.
3 Test Option (1): E⃗=B⃗=j^+k^  ⟹  E⃗×B⃗=0⃗\vec{E} = \vec{B} = \hat{j} + \hat{k} \implies \vec{E} \times \vec{B} = \vec{0} (False).
4 Test Option (2): (−j^+k^)×(−j^−k^)=2i^(-\hat{j} + \hat{k}) \times (-\hat{j} - \hat{k}) = 2\hat{i} (Points along +i^+\hat{i}! True!).
5 Test Option (3): Antiparallel   ⟹  E⃗×B⃗=0⃗\implies \vec{E} \times \vec{B} = \vec{0} (False).
6 Test Option (4): Parallel   ⟹  E⃗×B⃗=0⃗\implies \vec{E} \times \vec{B} = \vec{0} (False).
7 Match Option (2).
🛡️
Why You Can 100% Trust This Shortcut: Canonical Maxwell's equations and Poynting vector electrodynamics for transverse EM waves.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Fundamental Orthogonality Relations of Electromagnetic Waves

In a transverse plane electromagnetic wave propagating in free space: 1. The electric field vector E⃗\vec{E} and magnetic field vector B⃗\vec{B} are perpendicular to each other: E⃗⋅B⃗=0\vec{E} \cdot \vec{B} = 0. 2. Both E⃗\vec{E} and B⃗\vec{B} are perpendicular to the wave propagation direction k^=i^\hat{k} = \hat{i} (so they lie in the yy-zz plane). 3. The direction of energy flow (Poynting vector) is along E⃗×B⃗\vec{E} \times \vec{B}:

c^=E⃗×B⃗∣E⃗×B⃗∣=+i^\hat{c} = \frac{\vec{E} \times \vec{B}}{|\vec{E} \times \vec{B}|} = +\hat{i}
Step 2

Evaluating the Vector Cross Product for Option (2)

For E⃗=−j^+k^\vec{E} = -\hat{j} + \hat{k} and B⃗=−j^−k^\vec{B} = -\hat{j} - \hat{k}: - Check orthogonality: E⃗⋅B⃗=(−1)(−1)+(1)(−1)=1−1=0\vec{E} \cdot \vec{B} = (-1)(-1) + (1)(-1) = 1 - 1 = 0 (orthogonal). - Compute cross product using standard cyclic unit vector rules (j^×k^=i^\hat{j} \times \hat{k} = \hat{i}, k^×j^=−i^\hat{k} \times \hat{j} = -\hat{i}):

E⃗×B⃗=∣i^j^k^0−110−1−1∣=i^[(−1)(−1)−(1)(−1)]=i^(1+1)=+2i^\vec{E} \times \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 0 & -1 & 1 \\ 0 & -1 & -1 \end{vmatrix} = \hat{i}\left[(-1)(-1) - (1)(-1)\right] = \hat{i}(1 + 1) = +2\hat{i}
Step 3

Refutation of Remaining Options

Options (1) and (4) have parallel vectors E⃗∥B⃗\vec{E} \parallel \vec{B}, yielding E⃗×B⃗=0⃗\vec{E} \times \vec{B} = \vec{0}. Option (3) has antiparallel vectors E⃗=−B⃗\vec{E} = -\vec{B}, also yielding E⃗×B⃗=0⃗\vec{E} \times \vec{B} = \vec{0}. None of these can propagate an electromagnetic wave.

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

Electric and magnetic fields are parallel (E⃗×B⃗=0⃗\vec{E} \times \vec{B} = \vec{0}), violating transversality and zero Poynting flux.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming E⃗\vec{E} and B⃗\vec{B} can point in the exact same direction.
2 2
✓ 100% Correct
Verdict & Scientific Reason:

Both vectors are mutually perpendicular (E⃗⋅B⃗=0\vec{E} \cdot \vec{B} = 0) and their cross product E⃗×B⃗=+2i^\vec{E} \times \vec{B} = +2\hat{i} points along the positive xx-direction.

💡
Why this is airtight: None; rigorous vector cross product analysis.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Vectors are antiparallel (E⃗×B⃗=0⃗\vec{E} \times \vec{B} = \vec{0}).

⚠️
Student Fallacy (Why candidates pick this trap): Confusing opposite signs with perpendicular orientation.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Identical vectors with zero cross product.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming identical phase implies identical spatial orientation.
⚠️

NTA Trap Alert: Cyclic Vector Cross Product Sign Trap

Students frequently compute k^×j^=+i^\hat{k} \times \hat{j} = +\hat{i} instead of −i^-\hat{i}, flipping the resulting cross product to −2i^-2\hat{i} and falsely eliminating the correct option.

🛡️ How to avoid the -1 mark: Use the standard determinant or cyclic rule: i^×j^=k^\hat{i} \times \hat{j} = \hat{k}, j^×k^=i^\hat{j} \times \hat{k} = \hat{i}, k^×j^=−i^\hat{k} \times \hat{j} = -\hat{i}.
📖

Core NEET Syllabus Standard

NCERT Physics · Electromagnetic Waves Standard Benchmark
Core Scientific Principle Tested:

"In an electromagnetic wave, electric and magnetic fields are mutually perpendicular and perpendicular to the direction of propagation, with S⃗∝E⃗×B⃗\vec{S} \propto \vec{E} \times \vec{B} defining the wave vector."

Syllabus Focus: Transverse Nature of Electromagnetic Waves
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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