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Q.41 Physics ⭐ 360° Option Elimination Active
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NEET 2026 Physics Question 41 Solution

Topic: Laws of Motion · Official NTA Booklet Code 50
NEET 2026 Physics Question 41: Optimum Banking Angle of a Circular Track for Minimum Tyre Wear

Question

A car travels on a circular racetrack of radius 50 m, which is banked at an angle θ. If the car travels at a speed 10 m s⁻¹, then the wear and tear on its tyres is minimum. Taking the acceleration due to gravity to be 10 m s⁻², the value of θ is:

✓
Verified Against NTA Final Answer Key
Option (1) : theta = tan^-1(1/5)
📚 Laws of Motion Easy
📋 Given Parameters & Problem Setup
Track Radius r = 50 m
Speed of Car v = 10 m/s
Acceleration due to Gravity g = 10 m/s^2
Condition Minimum wear and tear on tyres (zero friction required)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Optimum Banking Formula Shortcut

⏱️ Instant recall saves 45 seconds.

Zero wear and tear means zero sideways friction: tan(theta) = v^2 / (r * g)!

1 Substitute: v^2 = 10^2 = 100.
2 Denominator: r * g = 50 * 10 = 500.
3 tan(theta) = 100 / 500 = 1/5.
4 theta = tan^-1(1/5). Solved in 5 seconds!
🛡️
Why You Can 100% Trust This Shortcut: When wear and tear is minimum, the horizontal component of the normal reaction N*sin(theta) provides 100% of the centripetal force m*v^2/r, while N*cos(theta) balances gravity m*g, giving tan(theta) = v^2 / (rg).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Understand the Physical Meaning of "Minimum Wear and Tear"

Tyre wear and tear occurs due to sideways frictional forces between the tyres and the road surface:

f=0(Ideal / Optimum Banking Condition)f = 0 \quad (\text{Ideal / Optimum Banking Condition})
  • • When a vehicle travels at the design speed on a banked road, no lateral friction is demanded.
  • • Centripetal acceleration is supplied entirely by the normal force from the inclined road surface.
Step 2

Set Up Dynamic Equilibrium Equations

Resolve the normal force N into horizontal and vertical components:

Nsin⁡θ=mv2r,Ncos⁡θ=mgN \sin\theta = \frac{m v^2}{r}, \qquad N \cos\theta = m g
  • • N*sin(theta) acts toward the center of the circular track.
  • • N*cos(theta) balances the vehicle weight.
Step 3

Divide Equations and Solve for theta

Divide the horizontal balance by the vertical balance:

tan⁡θ=v2rg=10250×10=100500=15  ⟹  θ=tan⁡−1(15)\tan\theta = \frac{v^2}{r g} = \frac{10^2}{50 \times 10} = \frac{100}{500} = \frac{1}{5} \implies \theta = \tan^{-1}\left(\frac{1}{5}\right)
  • • Matches Option (1) exactly.
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 Option (1)
✓ 100% Correct
Verdict & Scientific Reason:

100% mathematically exact; confirmed by Official NTA Final Answer Key.

💡
Why this is airtight: Direct application of optimum banking angle formula tan(theta) = v^2 / (rg).
Note: Flawless physics.
2 Option (2)
✗ Incorrect
Verdict & Scientific Reason:

Arithmetic factor of 2 error.

⚠️
Student Fallacy (Why candidates pick this trap): Uses r = 25 or multiplies numerator by 2.
Note: v^2 / (rg) = 100 / 500 = 1/5.
3 Option (3)
✗ Incorrect
Verdict & Scientific Reason:

Confuses with 30 or 60 degree standard angles.

⚠️
Student Fallacy (Why candidates pick this trap): Attempts to force a special triangle angle.
Note: Banking angles are derived from parameters, not standard trigonometry.
4 Option (4)
✗ Incorrect
Verdict & Scientific Reason:

Inverted and multiplied.

⚠️
Student Fallacy (Why candidates pick this trap): Arbitrary distractor.
Note: tan(theta) = 1/5.
⚠️

NTA Trap Alert: Confusing Optimum Speed with Maximum Friction Speed

Students who look for friction coefficient mu panic because mu is not given in the question.

🛡️ How to avoid the -1 mark: Remember: The phrase "wear and tear is minimum" ALWAYS means friction is ZERO! Set f = 0 ==> tan(theta) = v^2 / (rg).
📖

Core NEET Syllabus Standard

NEET UG Physics Core Standards · Laws of Motion Standard Benchmark
Core Scientific Principle Tested:

"Optimum banking angle of a circular road: tan(theta) = v^2 / (r*g). At this speed, a vehicle can navigate the turn safely even on frictionless ice."

Syllabus Focus: Circular Motion & Banking of Curved Roads
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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