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NEET 2026 Chemistry Question 90 Solution

Topic: Chemical Bonding and Molecular Structure · Official NTA Booklet Code 50
NEET 2026 Chemistry Question 90: Highest Occupied Molecular Orbital (HOMO) in Second-Row Diatomics

Question

The highest occupied molecular orbital for Ne₂ is

✓
Verified Against NTA Final Answer Key
Option (4) : σ*_{2p}
📚 Chemical Bonding and Molecular Structure Easy
📋 Given Parameters & Problem Setup
Diatomic Species Ne₂ (Neon dimer)
Total Electron Count 2 × 10 = 20 electrons
Target Highest Occupied Molecular Orbital (HOMO)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Full 20-Electron MOT Sequence

⏱️ Save ~45 seconds

Ne₂ fills all available second-row molecular orbitals up to the very highest antibonding level: σ*_{2p}!

1 Total electrons in Ne₂ = 10 + 10 = 20 electrons.
2 Molecular orbital filling order for elements with Z > 7 (O₂, F₂, Ne₂):
3 σ_{1s}² σ*_{1s}² σ_{2s}² σ*_{2s}² σ_{2p_z}² (π_{2p_x}² = π_{2p_y}²) (π*_{2p_x}² = π*_{2p_y}²) σ*_{2p_z}².
4 All 20 electrons completely fill orbitals up to the final σ*_{2p} level.
5 Therefore, the Highest Occupied Molecular Orbital (HOMO) is σ*_{2p}!
6 Option (4) is undeniably correct in 5 seconds flat!
🛡️
Why You Can 100% Trust This Shortcut: Universal molecular orbital theory: Second-row diatomic molecules with 20 electrons fill all bonding and antibonding molecular orbitals generated from 1s, 2s, and 2p valence atomic orbitals, ending at σ*_{2p} (bond order = (10 - 10)/2 = 0).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Calculate Total Number of Electrons in Ne₂

Neon has atomic number Z = 10. A hypothetical homonuclear diatomic neon molecule (Ne₂) contains 2 × 10 = 20 electrons.

Ntotal=10+10=20 electronsN_{\text{total}} = 10 + 10 = 20\text{ electrons}
  • • Core electrons from 1s: 4 electrons.
  • • Valence electrons from 2s and 2p: 16 electrons.
Step 2

Construct the Complete Molecular Orbital Configuration

For homonuclear diatomics with Z > 7, no significant 2s-2p mixing occurs. The molecular orbitals are ordered by increasing energy: σ_{1s} < σ*_{1s} < σ_{2s} < σ*_{2s} < σ_{2p_z} < (π_{2p_x} = π_{2p_y}) < (π*_{2p_x} = π*_{2p_y}) < σ*_{2p_z}

σ1s2  σ1s∗2  σ2s2  σ2s∗2  σ2pz2  (π2px2=π2py2)  (π2px∗2=π2py∗2)  σ2pz∗2\sigma_{1s}^2\; \sigma_{1s}^{*2}\; \sigma_{2s}^2\; \sigma_{2s}^{*2}\; \sigma_{2p_z}^2\; (\pi_{2p_x}^2 = \pi_{2p_y}^2)\; (\pi_{2p_x}^{*2} = \pi_{2p_y}^{*2})\; \sigma_{2p_z}^{*2}
  • • Total electrons accommodated = 2 + 2 + 2 + 2 + 2 + 4 + 4 + 2 = 20 electrons.
Step 3

Identify the Highest Occupied Molecular Orbital (HOMO)

The orbital of highest energy that contains electrons in the ground-state electron configuration is defined as the HOMO. In Ne₂, the last two electrons occupy the σ*_{2p_z} (antibonding σ_{2p}) orbital.

HOMO(Ne2)≡σ2p∗\text{HOMO}(\text{Ne}_2) \equiv \sigma^*_{2p}
  • • HOMO is σ*_{2p}.
  • • Matches Option (4).
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. π_{2p} holds electrons 11 through 14, well below the highest occupied orbital.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing bonding π orbitals with highest occupied level.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. σ_{2p} holds electrons 9 and 10, far lower in energy than the antibonding orbitals.

⚠️
Student Fallacy (Why candidates pick this trap): Thinking of bonding orbitals only.
3 C
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. π*_{2p} is the HOMO for O₂ (16 electrons) and F₂ (18 electrons), but Ne₂ has 20 electrons.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing the HOMO of F₂ with the HOMO of Ne₂.
4 D
✓ 100% Correct
Verdict & Scientific Reason:

Exact match: With 20 electrons, the last orbital filled is the antibonding σ*_{2p} orbital.

💡
Why this is airtight: None; flawless mastery of Molecular Orbital Theory.
⚠️

NTA Trap Alert: Assuming F₂ and Ne₂ Share the Same HOMO

Students frequently memorize that F₂ (18 electrons) has HOMO = π*_{2p}. Ne₂ has 20 electrons, adding 2 more electrons that occupy the final higher-energy σ*_{2p} orbital!

🛡️ How to avoid the -1 mark: Count all 20 electrons: F₂ stops at π*_{2p} (18 e⁻); Ne₂ fills the final σ*_{2p} (20 e⁻).
📖

Core NEET Syllabus Standard

NEET Chemistry Core Syllabus · Chemical Bonding and Molecular Structure Standard Benchmark
Core Scientific Principle Tested:

"In diatomic second-row molecules with 20 electrons, all 2p bonding and antibonding orbitals are completely filled."

Syllabus Focus: Molecular Orbital Theory - Energy level diagrams and electronic configurations
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
20 electrons fill the cup right to the top: σ*_{2p} is the final stop!

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