NEET 2026 Chemistry Question 90 Solution
Question
The highest occupied molecular orbital for Ne₂ is
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The highest occupied molecular orbital for Ne₂ is
Ne₂ fills all available second-row molecular orbitals up to the very highest antibonding level: σ*_{2p}!
Neon has atomic number Z = 10. A hypothetical homonuclear diatomic neon molecule (Ne₂) contains 2 × 10 = 20 electrons.
For homonuclear diatomics with Z > 7, no significant 2s-2p mixing occurs. The molecular orbitals are ordered by increasing energy: σ_{1s} < σ*_{1s} < σ_{2s} < σ*_{2s} < σ_{2p_z} < (π_{2p_x} = π_{2p_y}) < (π*_{2p_x} = π*_{2p_y}) < σ*_{2p_z}
The orbital of highest energy that contains electrons in the ground-state electron configuration is defined as the HOMO. In Ne₂, the last two electrons occupy the σ*_{2p_z} (antibonding σ_{2p}) orbital.
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect. π_{2p} holds electrons 11 through 14, well below the highest occupied orbital.
Incorrect. σ_{2p} holds electrons 9 and 10, far lower in energy than the antibonding orbitals.
Incorrect. π*_{2p} is the HOMO for O₂ (16 electrons) and F₂ (18 electrons), but Ne₂ has 20 electrons.
Exact match: With 20 electrons, the last orbital filled is the antibonding σ*_{2p} orbital.
Students frequently memorize that F₂ (18 electrons) has HOMO = π*_{2p}. Ne₂ has 20 electrons, adding 2 more electrons that occupy the final higher-energy σ*_{2p} orbital!
"In diatomic second-row molecules with 20 electrons, all 2p bonding and antibonding orbitals are completely filled."
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