NEET 2025 Physics Question 40 Solution
Question
A full wave rectifier circuit with diodes (D₁) and (D₂) is shown in the figure. If input supply voltage Vᵢₙ = 220 sin(100πt) volt, then at t = 15 msec
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A full wave rectifier circuit with diodes (D₁) and (D₂) is shown in the figure. If input supply voltage Vᵢₙ = 220 sin(100πt) volt, then at t = 15 msec
Phase θ = 100π × 15×10⁻³ = 1.5π = 270° ⟹ sin(270°) = -1 (Negative Peak). In any half-cycle, one diode is forward biased and the other is reverse biased. Since transformer dot convention was omitted, NTA awarded marks for both Option (1) and Option (2)!
Substitute t = 15 × 10⁻³ s into the input voltage waveform:
In a center-tapped transformer, the secondary voltage is split equally into two halves with respect to the center tap (which serves as the zero-potential reference):
The schematic does not specify dot convention on the transformer core:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Officially accepted by NTA (A,B). Correct under 180° inverted secondary winding convention.
Officially accepted by NTA (A,B). Correct under standard non-inverting secondary winding convention.
Incorrect. In a center-tapped full-wave rectifier, both diodes can never conduct simultaneously.
Incorrect. One terminal of the secondary is always positive while the other is negative.
A frequent student misconception is that "full wave" means both diodes are on at the same time. In reality, each diode conducts strictly for alternate half-cycles (180° each), taking turns!
"In a full-wave rectifier, diodes conduct alternately during opposite half-cycles."
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