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Q.8 Physics · Section A ⭐ 360° Option Elimination Active
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NEET 2024 Physics Question 8 Solution

Topic: Gravitation · Official NTA Booklet Code T1
NEET 2024 Physics Question 8: Acceleration Due to Gravity on an Arbitrary Planet

Question

The mass of a planet is 1/10th that of the earth and its diameter is half that of the earth. The acceleration due to gravity on that planet is:

✓
Verified Against NTA Final Answer Key
Option (2) : 3.92 m s⁻²
📚 Gravitation Easy
📋 Given Parameters & Problem Setup
Planet mass ratio M_p = M_e / 10
Planet diameter ratio D_p = D_e / 2 => R_p = R_e / 2
Earth surface gravity g_e = 9.8 m s⁻²
⚡

The 30-Second Exam Hall Shortcut: ⚡ Proportionality Scaling Hack

⏱️ Save ~40 seconds

g ∝ M / R² -> g_p = g_e × (1/10) / (1/2)² = 9.8 × 4 / 10 = 3.92 m s⁻²!

1 Surface gravity formula: g = GM / R².
2 Mass scales by factor of 1/10.
3 Radius scales by factor of 1/2, so R² scales by (1/2)² = 1/4.
4 Ratio: g_p / g_e = (1/10) / (1/4) = 4 / 10 = 0.4.
5 g_p = 0.4 × 9.8 = 3.92 m s⁻². Pick Option (2) in under 10 seconds!
🛡️
Why You Can 100% Trust This Shortcut: Newton’s Law of Universal Gravitation (Surface gravity formula: g = GM/R²).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Governing Formula for Surface Gravity

The acceleration due to gravity on the surface of a spherical celestial body of mass M and radius R is given by Newton’s law of gravitation:

g=GMR2g = \frac{G M}{R^2}
Step 2

Ratio Formation

Writing the ratio of the planet’s surface gravity g_p to Earth’s surface gravity g_e:

gpge=(MpMe)(ReRp)2\frac{g_p}{g_e} = \left(\frac{M_p}{M_e}\right) \left(\frac{R_e}{R_p}\right)^2
Step 3

Substitution of Scaling Factors

Given that M_p = M_e / 10 and diameter is halved (meaning radius R_p = R_e / 2):

gpge=(110)(ReRe/2)2=110×22=410=0.4\frac{g_p}{g_e} = \left(\frac{1}{10}\right) \left(\frac{R_e}{R_e / 2}\right)^2 = \frac{1}{10} \times 2^2 = \frac{4}{10} = 0.4
Step 4

Numerical Evaluation

Multiplying by standard Earth surface gravity g_e = 9.8 m s⁻²:

gp=0.4×9.8 m s−2=3.92 m s−2g_p = 0.4 \times 9.8\,\text{m s}^{-2} = 3.92\,\text{m s}^{-2}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

Occurs if radius is not squared in the denominator (9.8 × 2 / 4 = 4.9).

⚠️
Student Fallacy (Why candidates pick this trap): Forgetting the square in the denominator: writing g ∝ M/R instead of M/R².
2 (2)
✓ 100% Correct
Verdict & Scientific Reason:

Exact solution: g_p = 0.4 × 9.8 = 3.92 m s⁻².

💡
Why this is airtight: None.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Twice of Earth gravity; occurs if mass is taken as doubled rather than one-tenth.

⚠️
Student Fallacy (Why candidates pick this trap): Inverting the mass and radius ratios.
4 (4)
✗ Incorrect
Verdict & Scientific Reason:

Standard Earth gravity; ignores the planet’s smaller mass and radius.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming planetary gravity is universally constant.
⚠️

NTA Trap Alert: Diameter vs Radius Confusion

Students often wonder if the ratio of diameters differs from the ratio of radii.

🛡️ How to avoid the -1 mark: Diameter ratio is identical to radius ratio: D_p/D_e = R_p/R_e. Always replace diameter ratio directly with radius ratio!
📖

Core NEET Syllabus Standard

Physics Core Mechanics · Gravitation Standard Benchmark
Core Scientific Principle Tested:

"Surface gravity is directly proportional to mass and inversely proportional to the square of the radius (g = GM/R²)."

Syllabus Focus: Acceleration Due to Gravity of the Earth and Planets
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
Radius halves -> Gravity quadruples; Mass drops 10x -> Multiply by 0.4 -> 3.92!

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